JAC444-Workshops 2 & 3 Solved

This second assignment lets you practice basic concepts such as encapsulation and abstraction, inheritance, polymorphism, and exceptions. 

 

In this assignment, you will be working with geometrical shapes such as: Circle, Square, 

Rectangle, Parallelogram, and Triangle. Use the following figure as a reference 

(you don’t need to calculate shapes’ area for this assignment): 

 

You will need to create geometrical shapes and calculate their perimeters. Therefore, you must develop java classes for all the geometrical shapes mentioned above (put all your classes in a package named shapes). Each class must be able to calculate the shape’s perimeter. For each class, you must provide implementations for toString(), at least one constructor, setters/getters, and the documentations for the entire class. 

You should also provide an interface Shape as the root of the inheritance hierarchy, and design the appropriate “is-a” relationships among the above-mentioned classes.  

A text file named shapes.txt has been given to you. The file contains the definitions of some geometrical shapes. Each line might define a geometrical shape with the following format: name,x,y,z. The name is the shape’s name and x,y,z are the values needed to define the shape’s dimensions. The empty line signals the end of the file. 

 

If a line is not properly formatted or it does not contain the necessary number of values to correctly describe a shape, your program must ignore that line. If you cannot build the geometrical shapes with the given values (ex. zero or negative values for dimensions, wrong values for three sides of a triangle, etc.), you should throw an exception. Therefore, there is a need to define some custom Exception classes for some of your classes. Your program must be capable of storing all the geometrical shapes read from the file in one data structure. Since arrays are the only data structure that we have covered so far, you must use just one array to contain all the shapes in this assignment. In future, while we cover collections in Java, you will figure out that other data structures could ease your programming tasks a lot! 

 

Copy the shapes.txt file in the root folder of your Java project in Eclipse. We would cover exceptions in week 4 and File IO in week 5, but if you want to start ahead of time, you could use the following code snippet to read all the lines from the file. You could also consider using the split() method of class String to split each line to its composing items: 

try (BufferedReader br = new BufferedReader(new FileReader(fileName))) { while ((s = br.readLine()) != null) { 

String[] tokens = s.split(","); 

//your code 

       } 

} catch (IOException e) { 

  System.out.println(e.getMessage()); } 

Do the following tasks in different modules (methods) of the Main class of your project: 

 

Task 1: Read the file Shapes.txt, create the shapes and store them in your data structure. Then print the number of shapes you created, and finally, print all the shapes and their calculated perimeters polymorphically. For the sample input file, sample output could be: 

 

-------JAC 444 Assignment 1<------- -------Task 1 ... <------- 

Invalid radius! 

Invalid side(s)! Invalid side! 

Invalid side(s)! 

 

32 shapes were created: 

Circle {r=1.0} perimeter = 6.28319 

 

Circle {r=2.111} perimeter = 13.2638 

 

Circle {r=1.1} perimeter = 6.91150 

 

Triangle {s1=3.0, s2=4.0, s3=5.0} perimeter = 12.0000 

 

Triangle {s1=3.9, s2=4.0, s3=5.9} perimeter = 13.8000 

 

Square {s=3.0} perimeter = 12.0000 

 

Parallelogram {w=4.0, h=9.0} perimeter = 26.0000 

 

Rectangle {w=3.0, h=5.1} perimeter = 16.2000 

 

Square {s=5.0} perimeter = 20.0000 

 

Parallelogram {w=3.9, h=9.2} perimeter = 26.2000 

 

Triangle {s1=4.9, s2=5.0, s3=8.9} perimeter = 18.8000  Rectangle {w=8.0, h=2.1} perimeter = 20.2000 

 

Circle {r=3.8} perimeter = 23.8761 

 

Parallelogram {w=3.1, h=9.8} perimeter = 25.8000 

 

Triangle {s1=3.1, s2=4.1, s3=5.1} perimeter = 12.3000  

Parallelogram {w=0.1, h=0.2} perimeter = 0.600000  

Triangle {s1=4.0, s2=5.0, s3=6.0} perimeter = 15.0000 

 

Rectangle {w=3.1, h=5.2} perimeter = 16.6000 

 

Circle {r=10.0} perimeter = 62.8319 

 

Square {s=0.1} perimeter = 0.400000 

 

Triangle {s1=3.1, s2=4.0, s3=5.0} perimeter = 12.1000 

 

Circle {r=2.0} perimeter = 12.5664 

 

Parallelogram {w=3.9, h=9.3} perimeter = 26.4000 

 

Parallelogram {w=1.1, h=1.2} perimeter = 4.60000 

 

Rectangle {w=3.0, h=5.2} perimeter = 16.4000 

 

Square {s=100.1} perimeter = 400.400 

 

Square {s=100.2} perimeter = 400.800 

 

Circle {r=10.1} perimeter = 63.4602 

 

Triangle {s1=3.0, s2=4.0, s3=5.0} perimeter = 12.0000 

 

Triangle {s1=3.9, s2=4.8, s3=5.7} perimeter = 14.4000 

 

Parallelogram {w=1.2, h=2.1} perimeter = 6.60000 

 

Square {s=1.0E-5} perimeter = 4.00000e-05 

 

 

Task 2: Delete the triangle with the minimum perimeter (there could be more than one minimum) and the circle with the maximum perimeter (there could be more than one maximum) from the shapes. Print the all the remaining shapes and their perimeters polymorphically. For the sample input file, sample output could be: 

 

-------Task 2 ... <------- 

Circle {r=1.0} perimeter = 6.28319 

 

Circle {r=2.111} perimeter = 13.2638 

 

Circle {r=1.1} perimeter = 6.91150 

 

Triangle {s1=3.9, s2=4.0, s3=5.9} perimeter = 13.8000  Square {s=3.0} perimeter = 12.0000 

 

Parallelogram {w=4.0, h=9.0} perimeter = 26.0000 

 

Rectangle {w=3.0, h=5.1} perimeter = 16.2000 

 

Square {s=5.0} perimeter = 20.0000 

 

Parallelogram {w=3.9, h=9.2} perimeter = 26.2000 

 

Triangle {s1=4.9, s2=5.0, s3=8.9} perimeter = 18.8000 

 

Rectangle {w=8.0, h=2.1} perimeter = 20.2000 

 

Circle {r=3.8} perimeter = 23.8761 

 

Parallelogram {w=3.1, h=9.8} perimeter = 25.8000 

 

Triangle {s1=3.1, s2=4.1, s3=5.1} perimeter = 12.3000  

Parallelogram {w=0.1, h=0.2} perimeter = 0.600000  

Triangle {s1=4.0, s2=5.0, s3=6.0} perimeter = 15.0000 

 

Rectangle {w=3.1, h=5.2} perimeter = 16.6000 

 

Circle {r=10.0} perimeter = 62.8319 

 

Square {s=0.1} perimeter = 0.400000 

 

Triangle {s1=3.1, s2=4.0, s3=5.0} perimeter = 12.1000 

 

Circle {r=2.0} perimeter = 12.5664 

 

Parallelogram {w=3.9, h=9.3} perimeter = 26.4000 

 

Parallelogram {w=1.1, h=1.2} perimeter = 4.60000 

 

Rectangle {w=3.0, h=5.2} perimeter = 16.4000 

 

Square {s=100.1} perimeter = 400.400 

 

Square {s=100.2} perimeter = 400.800 

 

Triangle {s1=3.9, s2=4.8, s3=5.7} perimeter = 14.4000 

 

Parallelogram {w=1.2, h=2.1} perimeter = 6.60000 

 

Square {s=1.0E-5} perimeter = 4.00000e-05 

 

 

Task 3: Calculate and print the total perimeter of all parallelograms and the total perimeter of all triangles. For the sample input file, sample output could be: 

 

-------Task 3 ... <------- 

Total perimeter of Parallelogram is: 116.19999999999999 

Total perimeter of Triangle is: 86.4