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GU4206/GR5206-Homework 1 Data Cleaning, EDA, R Graphics, Filtering and Vectorized Commands Solved

Data cleaning, EDA, R graphics, more practice with filtering and vectorized commands.

Part 1: Loading, Cleaning the Exploring Data in R

i.             Load the data into a dataframe called housing.

ii.           How many rows and columns does the dataframe have?

iii.        Run the appropriate function to display the variable names of the dataframe.

iv.         Run this command, and explain, in words, what this does:

apply(is.na(housing), 2, sum).

v.           Remove the rows of the dataset for which the variable Value is NA.

vi.         How many rows did you remove with the previous call? Does this agree with your result from (iv)?

vii.       Calculate the third quartile of the property values, i.e., the third quartile Q3 is the 75th percentile. Use the quantile() function to complete this task.

viii.    Create a new variable in the dataset called HighValue that is equal to “High” if the property’s value is greater than Q3 and is equal to “NotHigh” if the property’s value is less than or equal to Q3.

ix.         Display a contingency table that shows the proprtions of HighValue split by Borough. Note that the table() function is the easiest way to tackle this problem but the table() function gives raw counts.

x.           What is the proportion of properties whose values are in the upper quartile and are located in The Bronx? Solve this question in two ways: (1) by using the table from (ix), and (2) by using logical/relational commands and using the function mean().

xi.         Given a randomly selected property is in The Bronx, what is the probability that its value is in the upper quartile? Solve this question in two ways: (1) by using the table from (ix), and (2) by using logical/relational/filtering commands and using the function mean().

xii.       Create a new variable in the dataset called logValue that is equal to the logarithm of the property’s Value. What are the minimum, median, mean, and maximum values of logValue?

xiii.     Create a new variable in the dataset called logUnits that is equal to the logarithm of the number of units in the property. The number of units in each piece of property is stored in the variable UnitCount.

xiv.     Finally create a new variable in the dataset called after1950 which equals TRUE if the property was built in or after 1950 and FALSE otherwise. You’ll want to use the YearBuilt variable here. This can be done in a single line of code.

Part 2: EDA

2i. Create a multiple boxplot (side-by-side boxplots) comparing property value across the five boroughs. Create a multiple boxplot (side-by-side boxplots) comparing property logValue across the five boroughs. Make sure to label the plots appropriately.

2ii. Plot property logValue against property logUnits. Name the x and y labels of the plot appropriately. logValue should be on the y-axis.

2iii. Make the same plot as above, but now include the argument col = factor(housing$after1950). Describe this plot and the covariation between the two variables. What does the coloring in the plot tell us?

Hint: legend("bottomright", legend = levels(factor(housing$after1950)), fill = unique(factor(housing$after1950))).

 

2iv. The cor() function calculates the correlation coefficient between two variables. What is the correlation between property logValue and property logUnits in (i) the whole data, (ii) just Manhattan (iii) just Brooklyn (iv) for properties built after 1950 (v) for properties built before 1950?

2v. Make a single plot showing property logValue against property logUnits for Manhattan and Brooklyn. When creating this plot, clearly distinguish the two boroughs.

2vi. Consider the following block of code. Give a single line of R code which gives the same final answer as the block of code. There are a few ways to do this.
manhat.props <- c()

for (props in 1:nrow(housing)) { if (housing$Borough[props] == "Manhattan") { manhat.props <- c(manhat.props, props) } }

med.value <- c() for (props in manhat.props) { med.value <- c(med.value, housing$Value[props])

}

med.value <- median(med.value, na.rm = TRUE)
 
2vii. For five boroughs, what are the median property values?

logValue.)
(Use Value here, not
 

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