ECE471-Lab 3 MD5 Collision Attack Lab Sovled

A secure one-way hash function needs to satisfy two properties: the one-way property and the collisionresistance property. The one-way property ensures that given a hash value h, it is computationally infeasible to find an input M, such that hash(M) = h. The collision-resistance property ensures that it is computationally infeasible to find two different inputs M1 and M2, such that hash(M1) = hash(M2).

Several widely-used one-way hash functions have trouble maintaining the collision-resistance property. At the rump session of CRYPTO 2004, Xiaoyun Wang and co-authors demonstrated a collision attack against MD5 [1]. In February 2017, CWI Amsterdam and Google Research announced the SHAttered attack, which breaks the collision-resistance property of SHA-1 [3]. While many students do not have trouble understanding the importance of the one-way property, they cannot easily grasp why the collision-resistance property is necessary, and what impact these attacks can cause.

The learning objective of this lab is for students to really understand the impact of collision attacks, and

 

see in first hand what damages can be caused if a widely-used one-way hash function’s collision-resistance property is broken. To achieve this goal, students need to launch actual collision attacks against the MD5 hash function. Using the attacks, students should be able to create two different programs that share the same MD5 hash but have completely different behaviors. This lab covers a number of topics described in the following:

•  One-way hash function

•  The collision-resistance property

•  Collision attacks

•  MD5

Lab Environment. This lab has been tested on our pre-built Ubuntu12.04 and Ubuntu16.04 VMs, both of which can be downloaded from the SEED website. The lab uses a tool called “Fast MD5 Collision Generation”, which was written by Marc Stevens; the name of the binary is called md5collgen in our VMs.

•  For Ubuntu16.04 VM: md5collgen has already been installed inside /home/seed/bin.

•  For Ubuntu12.04 VM: you need to download a zip file (md5patch.zip) from this lab’s web page, and run a simple shell script (patch.sh) to install the md5collgen program.

•  If you are interested in installing the tool to your own machine, you can download the source code directly from https://www.win.tue.nl/hashclash/.

Acknowledgment This lab was developed with the help of Vishtasp Jokhi, a graduate student in the Department of Electrical Engineering and Computer Science at Syracuse University.

1        Lab Tasks
1.1       Task 1: Generating Two Different Files with the Same MD5 Hash
In this task, we will generate two different files with the same MD5 hash values. The beginning parts of these two files need to be the same, i.e., they share the same prefix. We can achieve this using the md5collgen program, which allows us to provide a prefix file with any arbitrary content. The way how the program works is illustrated in Figure 1. The following command generates two output files, out1.bin and out2.bin, for a given a prefix file prefix.txt:

$ md5collgen -p prefix.txt -o out1.bin out2.bin

 

Figure 1: MD5 collision generation from a prefix

We can check whether the output files are distinct or not using the diff command. We can also use the md5sum command to check the MD5 hash of each output file. See the following commands.

$ diff out1.bin out2.bin

$ md5sum out1.bin

$ md5sum out2.bin

Since out1.bin and out2.bin are binary, we cannot view them using a text-viewer program, such as cat or more; we need to use a binary editor to view (and edit) them. We have already installed a hex editor software called bless in our VM. Please use such an editor to view these two output files, and describe your observations. In addition, you should answer the following questions:

–   Question 1. If the length of your prefix file is not multiple of 64, what is going to happen?

–   Question 2. Create a prefix file with exactly 64 bytes, and run the collision tool again, and see what happens.

–   Question 3. Are the data (128 bytes) generated by md5collgen completely different for the two output files? Please identify all the bytes that are different.

1.2       Task 2: Understanding MD5’s Property
In this task, we will try to understand some of the properties of the MD5 algorithm. These properties are important for us to conduct further tasks in this lab. MD5 is a quite complicated algorithm, but from very high level, it is not so complicated. As Figure 2 shows, MD5 divides the input data into blocks of 64 bytes, and then computes the hash iteratively on these blocks. The core of the MD5 algorithm is a compression function, which takes two inputs, a 64-byte data block and the outcome of the previous iteration. The compression function produces a 128-bit IHV, which stands for “Intermediate Hash Value”; this output is then fed into the next iteration. If the current iteration is the last one, the IHV will be the final hash value. The IHV input for the first iteration (IHV0) is a fixed value.

 

Figure 2: How the MD5 algorithm works

Based on how MD5 works, we can derive the following property of the MD5 algorithm: Given two inputs M and N, if MD5(M) = MD5(N), i.e., the MD5 hashes of M and N are the same, then for any input T, MD5(M k T) = MD5(N k T), where k represents concatenation.

That is, if inputs M and N have the same hash, adding the same suffix T to them will result in two outputs that have the same hash value. This property holds not only for the MD5 hash algorithm, but also for many other hash algorithms. Your job in this task is to design an experiment to demonstrates that this property

 

holds for MD5.

You can use the cat command to concatenate two files (binary or text files) into one. The following command concatenates the contents of file2 to the contents of file1, and places the result in file3.

$ cat file1 file2 file3

1.3       Task 3: Generating Two Executable Files with the Same MD5 Hash
In this task, you are given the following C program. Your job is to create two different versions of this program, such that the contents of their xyz arrays are different, but the hash values of the executables are the same.

#include <stdio.h

unsigned char xyz[200] = {

/* The actual contents of this array are up to you */

};

int main()

{ int i; for (i=0; i<200; i++){ printf("%x", xyz[i]);

}

printf("\n");

}
You may choose to work at the source code level, i.e., generating two versions of the above C program, such that after compilation, their corresponding executable files have the same MD5 hash value. However, it may be easier to directly work on the binary level. You can put some random values in the xyz array, compile the above code to binary. Then you can use a hex editor tool to modify the content of the xyz array directly in the binary file.

Finding where the contents of the array are stored in the binary is not easy. However, if we fill the array with some fixed values, we can easily find them in the binary. For example, the following code fills the array with 0x41, which is the ASCII value for letter A. It will not be difficult to locate 200 A’s in the binary.

unsigned char xyz[200] = {

0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41,

0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41,

0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, ... (omitted) ...

0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, 0x41, }
Guidelines. From inside the array, we can find two locations, from where we can divide the executable file into three parts: a prefix, a 128-byte region, and a suffix. The length of the prefix needs to be multiple of 64 bytes. See Figure 3 for an illustration of how the file is divided.

 

Figure 3: Break the executable file into three pieces.

We can run md5collgen on the prefix to generate two outputs that have the same MD5 hash value. Let us use P and Q to represent the second part (each having 128 bytes) of these outputs (i.e., the part after the prefix). Therefore, we have the following:

MD5 (prefix k P) = MD5 (prefix k Q)

Based on the property of MD5, we know that if we append the same suffix to the above two outputs, the resultant data will also have the same hash value. Basically, the following is true for any suffix:

MD5 (prefix k P k suffix) = MD5 (prefix k Q k suffix)

Therefore, we just need to use P and Q to replace 128 bytes of the array (between the two dividing points), and we will be able to create two binary programs that have the same hash value. Their outcomes are different, because they each print out their own arrays, which have different contents.

Tools. You can use bless to view the binary executable file and find the location for the array. For dividing a binary file, there are some tools that we can use to divide a file from a particular location. The head and tail commands are such useful tools. You can look at their manuals to learn how to use them. We give three examples in the following:

$ head -c 3200 a.out prefix

$ tail -c 100 a.out suffix

$ tail -c +3300 a.out suffix

The first command above saves the first 3200 bytes of a.out to prefix. The second command saves the last 100 bytes of a.out to suffix. The third command saves the data from the 3300th byte to the end of the file a.out to suffix. With these two commands, we can divide a binary file into pieces from any location. If we need to glue some pieces together, we can use the cat command.

If you use bless to copy-and-paste a block of data from one binary file to another file, the menu item "Edit - Select Range" is quite handy, because you can select a block of data using a starting point and a range, instead of manually counting how many bytes are selected.

1.4       Task 4: Making the Two Programs Behave Differently
In the previous task, we have successfully created two programs that have the same MD5 hash, but their behaviors are different. However, their differences are only in the data they print out; they still execute the same sequence of instructions. In this task, we would like to achieve something more significant and more meaningful.

Assume that you have created a software which does good things. You send the software to a trusted authority to get certified. The authority conducts a comprehensive testing of your software, and concludes that your software is indeed doing good things. The authority will present you with a certificate, stating that your program is good. To prevent you from changing your program after getting the certificate, the MD5 hash value of your program is also included in the certificate; the certificate is signed by the authority, so you cannot change anything on the certificate or your program without rendering the signature invalid.

You would like to get your malicious software certified by the authority, but you have zero chance to achieve that goal if you simply send your malicious software to the authority. However, you have noticed that the authority uses MD5 to generate the hash value. You got an idea. You plan to prepare two different programs. One program will always execute benign instructions and do good things, while the other program will execute malicious instructions and cause damages. You find a way to get these two programs to share the same MD5 hash value.

You then send the benign version to the authority for certification. Since this version does good things, it will pass the certification, and you will get a certificate that contains the hash value of your benign program. Because your malicious program has the same hash value, this certificate is also valid for your malicious program. Therefore, you have successfully obtained a valid certificate for your malicious program. If other people trusted the certificate issued by the authority, they will download your malicious program.

The objective of this task is to launch the attack described above. Namely, you need to create two pro-

 

grams that share the same MD5 hash. However, one program will always execute benign instructions, while the other program will execute malicious instructions. In your work, what benign/malicious instructions are executed is not important; it is sufficient to demonstrate that the instructions executed by these two programs are different.

Guidelines. Creating two completely different programs that produce the same MD5 hash value is quite hard. The two hash-colliding programs produced by md5collgen need to share the same prefix; moreover, as we can see from the previous task, if we need to add some meaningful suffix to the outputs produced by md5collgen, the suffix added to both programs also needs to be the same. These are the limitations of the MD5 collision generation program that we use. Although there are other more complicated and more advanced tools that can lift some of the limitations, such as accepting two different prefixes [2], they demand much more computing power, so they are out of the scope for this lab. We need to find a way to generate two different programs within the limitations.

There are many ways to achieve the above goal. We provide one approach as a reference, but students are encouraged to come up their own ideas. Instructors may consider rewarding students for their own ideas. In our approach, we create two arrays X and Y. We compare the contents of these two arrays; if they are the same, the benign code is executed; otherwise, the malicious code is executed. See the following pseudo-code:

Array X; Array Y;

main() { if(X’s contents and Y’s contents are the same) run benign code;

else run malicious code;

return;

}
We can initialize the arrays X and Y with some values that can help us find their locations in the executable binary file. Our job is to change the contents of these two arrays, so we can generate two different versions that have the same MD5 hash. In one version, the contents of X and Y are the same, so the benign code is executed; in the other version, the contents of X and Y are different, so the malicious code is executed. We can achieve this goal using a technique similar to the one used in Task 3. Figure 4 illustrates what the two versions of the program look like.

 

Figure 4: An approach to generate two hash-colliding programs with different behaviors.

From Figure 4, we know that these two binary files have the same MD5 hash value, as long as P and Q are generated accordingly. In the first version, we make the contents of arrays X and Y the same, while in the second version, we make their contents different. Therefore, the only thing we need to change is the contents of these two arrays, and there is no need to change the logic of the programs.