$25
Classify the following statements as being one of the following, where x and y are arbitrary propositions, and justify your answers (e.g., using a truth table)
• True for all combinations of x and y (Tautology)
• False for all combinations of x and y (Contradiction)
• Neither
(a) x∧(x =⇒ y)∧(¬y)
(b) x =⇒ (x∨y)
(c) (x∨y)∨(x∨¬y)
(d) (x =⇒ y)∨(x =⇒ ¬y)
(e) (x∨y)∧(¬(x∧y))
(f) (x =⇒ y)∧(¬x =⇒ y)∧(¬y)
2 Miscellaneous Logic
(a) Let the statement, (∀x ∈ R)(∃y ∈ R) G(x,y), be true for predicate G(x,y).
For each of the following statements, decide if the statement is certainly true, certainly false, or possibly true, and justify your solution. (If possibly true, provide a specific example where the statement is false and a specific example where the statement is true.)
(i) G(3,4)
(ii) (∀x ∈ R) G(x,3)
(iii) ∃y G(3,y)
(iv) ∀y ¬G(3,y)
(v) ∃x G(x,4)
(b) Give an expression using terms involving ∨,∧ and ¬ which is true if and only if exactly one of X,Y, and Z is true.
3 Propositional Practice
Convert the following English sentences into propositional logic and the following propositions into English. State whether or not each statement is true with brief justification.
(a) There is a real number which is not rational.
(b) All integers are natural numbers or are negative, but not both.
(c) If a natural number is divisible by 6, it is divisible by 2 or it is divisible by 3.
(d) (∀x ∈ R)(x ∈ C)
(e) (∀x ∈ Z)(((2 | x)∨(3 | x)) =⇒ (6 | x)) (f) (∀x ∈ N)((x 7) =⇒ ((∃a,b ∈ N)(a+b = x)))
4 Proof by?
(a) Prove that if for any two integers x and y, if 10 does not divide xy, then 10 does not divide x and 10 does not divide y. In notation: (∀x,y ∈ Z) (10 - xy) =⇒ ((10 - x) ∧ (10 - y)). What proof technique did you use?
(b) Prove or disprove the contrapositive.
(c) Prove or disprove the converse.
5 Prove or Disprove
(a) (∀n ∈ N) if n is odd then n2 +2n is odd.
(b) (∀x,y ∈ R) min(x,y)=(x+y−|x−y|)/2.
(c) (∀a,b ∈ R) if a+b ≤ 10 then a ≤ 7 or b ≤ 3.
(d) (∀r ∈ R) if r is irrational then r+1 is irrational.
(e) (∀n ∈ Z+) 10n2 n!.
6 Preserving Set Operations
For a function f, define the image of a set X to be the set f(X)= {y | y = f(x) for some x ∈ X}. Define the inverse image or preimage of a set Y to be the set f−1(Y)= {x | f(x) ∈ Y}. Prove the following statements, in which A and B are sets. By doing so, you will show that inverse images preserve set operations, but images typically do not.
Hint: For sets X and Y, X =Y if and only if X ⊆Y and Y ⊆ X. To prove that X ⊆Y, it is sufficient to show that (∀x)((x ∈ X) =⇒ (x ∈Y)).
(a) f−1(A∪B)= f−1(A)∪ f−1(B). (b) f−1(A∩B)= f−1(A)∩ f−1(B).
(c) f−1(A\B)= f−1(A)\ f−1(B).
(d) f(A∪B)= f(A)∪ f(B).
(e) f(A∩B) ⊆ f(A)∩ f(B), and give an example where equality does not hold.
(f) f(A\B) ⊇ f(A)\ f(B), and give an example where equality does not hold.