$25
In addition to the similarities and difference from Class 01, list 5 other ways in which eyes and cameras are similar. List 5 other ways in which they are different
Prove that for a thin lens, the image is in focus when
passes through the lens, then bends to pass through focal point (0, ππ) before hitting the image plane at ππβππ = (π¦π¦ππ, π§π§ππ). If the image is in focus, then similarly, a ray leaving the object at ππβπ€π€passing through the negative focal point (0, −ππ) will be bent parallel to the z axis and hit the image plane at the same point ππβππ.
Hint: As discussed in class, consider similar triangles from the lens to the focal point and the focal point to the image plane. There are 2 pairs of similar triangles, one for the positive and negative focal point. Then show that
−π§π§ππππ + π§π§π€π€ππ = π§π§πππ§π§π€π€
Suppose that, in the imaging geometry above, the image plane is located distance π§π§ππ′ =
π§π§ππ + βπ§π§ from the lens, so that the image is out of focus. Show that the blur circle has
|βπ§π§| diameter π·π· = ππ π§π§ππ , where d is the lens diameter.
Hint: Consider rays coming from the top and bottom of the lens that would be in focus at π§π§ππ.
What happens when they hit the image plane at π§π§ππ′?
A typical human eyeball is 2.4 cm in diameter and contains roughly 150,000,000 receptors.
Ignoring the fovea, assume that the receptors are uniformly distributed across a hemisphere (it is actually closer to 160°).
How many receptors are there per mm2?
Mars has a diameter of 8,000 km and an average distance from Earth of 225,000,000 km. Using a value of f equal to the eye’s diameter, on how many receptors does the image of Mars fall?
Show that a ray in the world projects to a line segment in the image as follows:
Define world ray π
π
π€π€ = π₯π₯βπ€π€|π₯π₯βπ€π€ = π π βπ€π€ + πΌπΌπ‘π‘βπ€π€, 0 ≤ πΌπΌ ≤ ∞. Show that it projects to camera line segment πΏπΏππ = π₯π₯βππ|π₯π₯βππ = (1 −π½π½)π π βππ + π½π½π‘π‘βππ where π π βππ is the projection of π π βπ€π€ onto the image plane and π‘π‘βππ is the projection of ray π
π
π€π€in the limit as πΌπΌ → ∞. You should find that π½π½ ranges from 0 to 1 and is related non-linearly to πΌπΌ.