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CS2250-Lab 3 Virtual Memory Management Solved

In this lab/programming assignment you will implement/simulate the operation of an Operating System’s Virtual Memory Manager which maps the virtual address spaces of multiple processes onto physical frames using page table translation. The assignment will assume multiple processes, each with its own virtual address space of exactly 64 virtual pages (yes this is small compared to the 1M entries for a full 32-address architecture), but the principle counts. As the sum of all virtual pages in all virtual address spaces may exceed the number of physical frames of the simulated system, paging needs to be implemented. The number of physical page frames varies and is specified by a program option, you have to support up to 128 frames; tests will only use 128 or less. Implementation is to be done in C/C++.

 

INPUT SPECIFICATION: 

 

The input to your program will be a comprised of:

1.      the number of processes (processes are numbered starting from 0)

2.      a specification for each process’ address space is comprised of

i.    the number of virtual memory areas / segments (aka VMAs)  ii. specification for each said VMA comprised of 4 numbers:

 “starting_virtual_page   ending_virtual_page  write_protected[0/1] filemapped[0/1]”

 

Following is a sample input with two processes. First line not starting with a ‘#’ is the number of processes. Processes in this sample have 2 and 3 VMAs, respectively. Note: ALL lines starting with ‘#’ must be ignored and are provided simply for documentation and readability. In particular, the first few lines are references that document how the input was created, though they are irrelevant to you. All provided inputs follow the format below, though number and location of lines with ‘#’ might vary.

 

#process/vma/page reference generator 

#       procs=2 #vmas=2 #inst=100 pages=64 %read=75.000000 lambda=1.000000 

#       holes=1 wprot=1 mmap=1 seed=19200 



#### process 0 



0 42 0 0 

43 63 1 0 

#### process 1 



0 17 0 1 

20 60 1 0 62 63 0 0

 

Since it is required that the VMAs of a single address space do not overlap, this property is guaranteed for all provided input files. However, there can potentially be holes between VMAs, which means that not all virtual pages of an address space are valid (i.e. assigned to a VMA). Each VMA is comprised of 4 numbers. start_vpage:           

end_vpage:           (note the VMA has    (end_vpage – start_vpage + 1)   virtual pages ) write_protected:   binary whether the VMA is write protected or not  

file_mapped:         binary to indicate whether the VMA is mapped to a file or not

  

The process specification is followed by a sequence of “instructions” and optional comment lines (see following example). An instruction line is comprised of a character (‘c’, ‘r’, ‘w’ or ‘e’) followed by a number.

“c <procid”:  specifies that a context switch to process #<procid is to be performed. It is guaranteed that the first instruction will always be a context switch instruction, since you must have an active pagetable in the MMU (in real systems).

“r <vpage”: implies that a load/read operation is performed on virtual page <vpage of the currently running process.

“w <vpage”: implies that a store/write operation is performed on virtual page <vpage of the currently running process. “e <procid”: current process exits, we guarantee that <procid is the current running proc, so you can ignore it.

 

##### example of an instruction sequence  ###### c 0 r 32 w 9 r 0 r 20 r 12 

You can assume that the input files are well formed as shown above, so fancy parsing is not required. Just make sure you take care of the ‘#’ comment lines. E.g. you can use sscanf(buf, “%d %d %d %d”,…) or  stream var1 var2 var3. 

 

DATA STRUCTURES:  

 

To approach this assignment, read in the specification and create process objects, each with its array/vector/list of vmas and a page_table that represents the translations from virtual pages to physical frames for that process.  

A page table naturally must contain exactly 64 page table entries (PTE). Please use constants rather than hardcoding “64”. A PTE is comprised of the PRESENT/VALID, REFERENCED, MODIFIED, WRITE_PROTECT, and PAGEDOUT bits and the number of the physical frame (in case the pte is present). This information can and must be implemented as a single 32bit value or as a bit structure (easier). It cannot be a structure of multiple integer values that collectively is larger than 32-bits. See http://www.cs.cf.ac.uk/Dave/C/node13.html (BitFields) or  http://www.catonmat.net/blog/bit-hacks-header-file/ as an example, I highly encourage you to use the first technique, let the compiler do the hard work for you.

Assuming that the maximum number of frames is 128, which equals 7 bits and the mentioned 5 bits above, you effectively have 32-12 = 20 bits for your own usage in the pagetable entry. You can use these bits at will (e.g. remembering whether a PTE is file mapped or not). What you can NOT do is run at the beginning of the program through the page table and mark each PTE with bits based on filemap or writeprotect. This is NOT how OSes do this due to hierarchical pagetable structures (not implemented in this lab though). You can only set those bits on the first page fault to that virtual page.

 

You must define a global frame_table that each operating system maintains to describe the usage of each of its physical frames and where you maintain reverse mappings to the process and the vpage that maps a particular frame. Note, that in this assignment a frame can only be mapped by at most one PTE at a time, which simplifies things significantly.

 

SIMULATION and IMPLEMENTATION:  

 

During each instruction you simulate the behavior of the hardware (shown below in blue) and hence you must check that the page is present. A special case are the ‘c’ (context switch) instruction which simply changes the current process and current page table pointer and the ‘e’ (process exit) instruction which exits a process.

 

Structure of the simulation 

 

The basic structure of the simulation should be something like the following:

 

typedef struct { … } pte_t;          // can only be total of 32-bit size and will check on this typedef struct { … } frame_t;  

 frame_t frame_table[MAX_FRAMES]; pte_t page_table[MAX_VPAGES];  // a per process array of fixed size=64 of pte_t  not pte_t pointers ! 

 

class Pager { 

        virtual frame_t* select_victim_frame() = 0;   // virtual base class  };  

frame_t *get_frame() { 

        frame_t *frame = allocate_frame_from_free_list();      if (frame == NULL) frame = THE_PAGER-select_victim_frame();        return frame; 

}  

while (get_next_instruction(&operation, &vpage)) {        // handle special case of “c” and “e” instruction        // now the real instructions for read and write 

       pte_t *pte = ¤t_process.page_table[vpage];// in reality this is done by hardware         if ( ! pte-present) { 

           // this in reality generates the page fault exception and now you execute 

           // verify this is actually a valid page in a vma if not raise error and next inst             frame_t *newframe = get_frame(); 

 

           //- figure out if/what to do with old frame if it was mapped 

           //   see general outline in MM-slides under Lab3 header 

           //   see whether and how to bring in the content of the access page. 

        } 

       // check write protection 

       // simulate instruction execution by hardware by updating the R/M PTE bits         update_pte(read/modify) bits based on operations.   

}   

 

When accessing a page (“r” or “w”) and the page is not present, as indicated by the associated PTE’s valid/present bit, the hardware would raise a page fault exception. Here you just simulate this by calling your (operating system’s) pagefault handler. In the pgfault handler you first determine that the vpage can be accessed, i.e. it is part of one of the VMAs. Maybe you can find a faster way then searching each time the VMA list as long as it does not involve doing that before the instruction simulation (see above, hint you have free bits in the PTE). If not, a SEGV output line must be created and you move on to the next instruction. If it is part of a VMA then the page must be instantiated, i.e. a frame must be allocated, assigned to the PTE belonging to the vpage of this instruction (i.e. currentproc-pagetable[vpage].frame = allocated_frame ) and then populated with the proper content. The population depends whether this page was previously paged out (in which case the page must be brought back from the swap space (“IN”) or (“FIN” in case it is a memory mapped file). If the vpage was never swapped out and is not file mapped, then by definition it still has a zero filled content and you issue the “ZERO” output.

 

That leaves the allocation of frames. All frames initially are in a free pool (use deque to get desired semantics). Once you run out of free frames, you must implement paging. We explore the implementation of several page replacement algorithms. Page replacement implies the identification of a victim frame according to the algorithm’s policy. This should be implemented as a derived class of a general Pager class with at least one virtual function  “frame_t* select_victim_frame();” that returns a victim frame (or returns int for the frame number). Once a victim frame has been determined, the victim frame must be unmapped from its user ( <address space:vpage), i.e. its entry in the owning process’s page_table must be removed  (“UNMAP”), however you must inspect the state of the R and M bits. If the page was modified, then the page frame must be paged out to the swap device (“OUT”) or in case it was file mapped written back to the file (“FOUT”). Now the frame can be reused for the faulting instruction. First the PTE must be reset (note once the PAGEDOUT flag is set it will never be reset as it indicates there is content on the swap device) and then the PTE’s frame must be set and the valid bit can be set.

 

At this point it is guaranteed, that the vpage is backed by a frame and the instruction can proceed in hardware (with the exception of the SEGV case above) and you have to set the REFERENCED and MODIFIED bits based on the operation. In case the instruction is a write operation and the PTE’s write protect bit is set (which it inherited from the VMA it belongs to) then a SEGPROT output line is to be generated. The page is considered referenced but not modified in this case.

 

Your code must actively maintain the PRESENT (aka valid), MODIFIED, REFERENCED, and PAGEDOUT bits and the frame index in the pagetable’s pte. The frame table is NOT updated by the simulated hardware as hardware has no access to the frame table. Only the pagetable entry (pte) is updated just as in real operating systems and hardware. The frame table can only be accessed as part of the “simulated page fault handler”  ( see code above ).

 

The following page replacement algorithms are to be implemented (letter indicates program option (see below)):

 

Algorithm
Based on Physical Frames
FIFO
F
Random
R
Clock  
C
Enhanced Second Chance / NRU
E
Aging
A
Working Set  
W
 

The page replacement code should be generic and the algorithms should be special instances of the page replacement class to avoid “switch/case statements” in the simulation of instructions. Use object oriented programming and inheritance.  

 

Since all replacement algorithms are based on frames, i.e. you are looping through the entire or parts of the frame table, and the reference and modified bits are only maintained in the page tables of processes, you need access to the PTEs. To be able to do that you should keep track of the reverse mapping from frame to PTE that is using it. Provide this reverse mapping

(frame ⇛ <proc-id,vpage) inside each frame’s frame table entry.

 

Note (again): you MUST NOT set any bits in the PTE before instruction simulation start, i.e. the pte (i.e. all bits) should be initialized to “0” before the instruction simulation starts. This is also true for assigning FILE or WRITEPROTECT bits from the VMA. This is to ensure that in real OSs the full page table (hierarchical) is created on demand;  on the first page fault on a particular pte, you have to search the vaddr in the VMA list. At that point you can store bits in the pte based on what you found in the VMA and what bits are not occupied by the mandatory bits (remember you have ~20 bits free here).

 

You are to create the following output if requested by an option (see at options description and set of options we grade with):

 

49: == r 4  UNMAP 1:42  OUT     IN      MAP 26 

 

Output 1 

69: == r 37  UNMAP 0:35  FIN       MAP 18 

 

 

Output 2 

75: == w 57  UNMAP 2:58  ZERO         MAP 17 

 

 

Output 3 

For instance, in Output 1 instruction 49 is a read operation on virtual page 4 of the current process. The replacement algorithms selected physical frame 26 that was used by virtual page 42 of process 1 (1:42) and hence first has to UNMAP the virtual page 42 of process 1 to avoid further access. Then because the page was dirty (modified) (this would have been tracked in the PTE) it pages the page OUT to a swap device with the (1:26) tag so the Operating system can find it later when process 1 references vpage 42 again (note you don’t implement the lookup). Then it pages IN the previously swapped out content of virtual page 4 of the current process (note this is where the OS would use <curprocid : vpage tag to find the swapped out page) into the physical frame 26, and finally maps it which makes the PTE_4 a valid/present entry and allows the access. Similarly, in output 2 a read operation is performed on virtual page 37. The replacement selects frame 18 that was mapped by process_0’s vpage=35. The page is not paged out, which indicates that it was not dirty/modified since the last mapping. The virtual page 37 is read from file (FIN) into physical frame 18 (implies it is file mapped) and finally mapped (MAP). In output 3 you see that frame 17 was selected forcing the unmapping of its current user process_2, vpage 58, the frame is zeroed, which indicates that the page was never paged out or written back to file (though it might have been unmapped previously see output 2). An operating system must zero pages on first access (unless filemapped) to guarantee consistent behavior. For filemapped virtual pages (i.e. part of filemapped VMA)\ even the initial content must be loaded from file.

 

In addition, your program needs to compute and print the summary statistics related to the VMM if requested by an option. This means it needs to track the number of segv, segprot, unmap, map, pageins (IN, FIN), pageouts (OUT, FOUT), and zero operations for each process and instructions, process exits, context switches globally. You have to compute the overall execution time in cycles, where the cost of operations (in terms of cycles) are as follows:   read/write (load/store) instructions count as 1, context_switches instructions=130, process exits instructions=1250.

In addition if the following operations counts as follows:  maps=300, unmaps=400, ins=3100, outs=2700, fins=2800, fouts=2400, zeros=140, segv=340, segprot=420  

 

Per process output:

     printf("PROC[%d]: U=%lu M=%lu I=%lu O=%lu FI=%lu FO=%lu Z=%lu SV=%lu SP=%lu\n",                      proc-pid, 

                     pstats-unmaps, pstats-maps, pstats-ins, pstats-outs,                      pstats-fins, pstats-fouts, pstats-zeros, 

                     pstats-segv, pstats-segprot); Summary output: 

   printf("TOTALCOST %lu %lu %lu %llu %lu\n",  

           inst_count, ctx_switches, process_exits, cost, sizeof(pte_t)); 

 

If requested by an option you have to print the relevant content of the page table of each process and the frame table.

 

PT[0]: * 1:RM- * * * 5:-M- * * 8:--- * * # * * * * * * * * # * * * 24:--- * * * # * * * * * * 

* * * # * * * * * * * * * # * * # * * * # * * * * * * * *  

FT: 0:1 0:5 0:24 0:8  

PROC[0]: U=25 M=29 I=1 O=8 FI=0 FO=0 Z=28 SV=0 SP=0 

TOTALCOST 31 1 0 52951 4 

 

Note, the total cost calculation can overrun 2^32 and you must account for that, so use 64-bit counters (unsigned long long). We will test your program with 1 million instructions. Also, the end calculations are tricky, so do them incrementally.

If you use individual 32-bit counters, don’t add up 32-bit numbers all at once and then assign to 64-bit, this will result in overflows. Add 32-bit numbers incrementally to the 64-bit counters.

Execution and Invocation Format: 

 

Your program must follow the following invocation:  

./mmu  –f<num_frames -a<algo  [-o<options] inputfile   randomfile       (arguments can be in any order → getopt()).      e.g. ./mmu -f4 -ac –oOPFS infile rfile selects the Clock Algorithm and creates output for operations, final page table content and final frame table content and summary line (see above). The outputs should be generated in that order if specified in the option string regardless how the order appears in the option string. We will grade the program with – oOPFS options (see below), run with varying page frame numbers and “diff” compare it to the expected output.

 

Test input files and the file with random numbers are supplied (same as lab2). The random file is required for the Random algorithm. Please reuse the code you have written for lab2, but note the difference in the modulo function which now indexes into [ 0, size ) vs previously ( 0, size ]. In the Random replacement algorithm you compute the frame selected as with (size==num_frames). As in the lab2 case, you increase the rofs and wrap around on overflow.  

 

•        The ‘O’ (ooooh nooooh) option shall generate the required output as shown in output-1/3.  

 

•        The ‘P’ (pagetable option) should print after the execution of all instructions the state of the pagetable:

As a single line for each process, you print the content of the pagetable pte entries as follows (shown for process 0).

 

PT[0]: 0:RMS 1:RMS 2:RMS 3:R-S 4:R-S 5:RMS 6:R-S 7:R-S 8:RMS 9:R-S 10:RMS 11:R-S 12:R-- 13:RM- # # 16:R-- 17:R-S # # 20:R-- # 22:R-S 23:RM- 24:RMS # # 27:R-S 28:RMS # # # # # 34:R-S 35:R-S # 37:RM- 38:R-S * # 41:R-- # 43:RMS 44:RMS # 46:R-S * * # * * * # 54:R-S # * * 58:RM- * * # * *  
 

R (referenced), M (modified), S (swapped out) (note we don’t show the write protection bit as it is implied/inherited from the specified VMA.

PTEs that are not valid are represented by a ‘#’ if they have been swapped out (note you don’t have to swap out a page if it was only referenced but not modified), or a ‘*’ if it does not have a swap area associated with. Otherwise (valid) indicates the virtual page index and RMS bits with ‘-‘ indicated that that bit is not set.

Note a virtual page, that was once referenced, but was not modified and then is selected by the replacement algorithm, does not have to be paged out (by definition all content must still be ZERO) and can transition to ‘*’.

 

•     The ‘F’ (frame table option) should print after the execution and should show which frame is mapped at the end to which <pid:virtual page or ‘*’ if not currently mapped by any virtual page.

 

FT: 0:32 0:42 0:4 1:8 * 0:39 0:3 0:44 1:19 0:29 1:61 * 1:58 0:6 0:27 1:34 
 

•        The ‘S’ option prints the summary line (“SUM …”) described above.

•        The ‘x’ option prints the current page table after each instructions (see example outputs) and this should help you significantly to track down bugs and transitions (remember you write the print function only once)

•        The ‘y’ option is like ‘x’ but prints the page table of all processes instead.

•        The ‘f’ option prints the frame table after each instruction.

•        The ‘a’ option prints additional “aging” information during victim_selecton and after each instruction for complex algorithms (not all algorithms have the details described in more detail below)

 

We will not test or use the ‘-f’ ,’-a’ or the ‘-x,-y’ options during the grading. It is purely for your benefit to add these and compare with the reference program under ~frankeh/Public/mmu   on any assigned cims machines. (Note only a max of 10 processes and 8 VMAs per process are supported in the reference program which means that is the max we test with).

 

All scanning replacement algorithm typically continue with the frame_index + 1 of the last selected victim frame.

 

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