$30
Questions with a (β) are each worth 1 bonus point for 453 students.
Let π ≥ 3 be given and let πΆπ be the π-cycle whose vertices are {0,1,2,… , π − 1}. Recall that ππ is an edge if and only if π = π + 1 mod π or π = π + 1 mod π.How many vertices does πΆπ × πΆπ have?
Show that πΆπ × πΆπ is 4-regular. One way is to let (π, π) be any vertex of πΆπ × πΆπ and explicitly show that (π, π) is adjacent to exactly four vertices.
How many edges does πΆπ × πΆπ have?
We discuss Cartesian products of regular graphs more generally.Let πΊ be an π-regular graph and π» be a π-regular graph. Show that πΊ × π» is an (π + π)-regular graph.
(β) Let πΊ be an π-regular graph. Show that πΊπ (this is the π-fold cartesian product πΊ × πΊ × β― × πΊ) is a ππ-regular graph. If you use mathematical induction, you may assume that πΊπ is isomorphic to πΊ × πΊπ−1.
Let π3 be the 3-cube with vertex set
π = {000,001,010,011,100,101,110,111}.
Give an example of two vertices such that if we delete them both, the graph πΊ that remains is a 6-cycle.
Suppose we start with π3 and produce the graph π» by identifying vertices 000 and 011; we call the resulting vertex π€. What is the degree of π€ in π»?
(β) What is the smallest number of edges we could delete from π3 so that the resulting graph is disconnected? Justify your answer.
Let πΊ be a graph with at least one edge.Show that for any π ≥ 1, if π is a walk in πΊ of length π, then there exists a walk π′ in πΊ of length π + 1. This shows that πΊ cannot have a longest walk.
Show that there is some upper bound π on the length of a path in πΊ. This means that if π is a walk of length π > π, then a vertex must be repeated in π. This shows that πΊ must have a
longest path.