COMP3350 -  Project #5  - Solved

Design: 

Create a BYTE array with the label ‘input’. This array may be of any length between 2 and 100. In the case of encryption ‘input’ will hold the plaintext and in the case of decryption ‘input’ will hold cypher-text.

Create a BYTE array with the label ‘key’. This array will have length between 1 and (LENGHTOF input -1). Meaning the lower bound for ‘key’ is one character and the upper bound is one less than the number of characters in ‘input’.

Create a BYTE variable named “options”. This variable will be used to determine which procedures should be executed. If ‘options’ contain the value 1 it means the program should execute encryption procedure. If ‘options’ contain the value 0 (or any other value than 1) the program should execute decryption procedure.

Create a BYTE array with the label ‘output’. This array will have a dynamic length equal to LENGTHOF input. When executing the program using encryption, the variable ‘output’ will hold the cypher-text and in the case of decryption, ‘output’ will hold plaintext.

You may create any other values you deem necessary.

You must have three procedures for this homework. The main procedure, a procedure to handle encryption, and another to handle the decryption. You may create other procedures if you wish.

Example of encryption / decryption:

For more information check the Wiki link: (https://en.wikipedia.org/wiki/ Vigenère_cipher)

The example below will use the plaintext word MEMORY and the key BAD.

First you “line up” your plaintext word with your key by writing the key directly beneath the plaintext word. Continue to repeat the key under each plaintext character:

MEMORY

BADBAD

In the above example MEMORY is longer than BAD, therefore, BAD was repeated. Next choose each character in the plaintext word, starting with the first and encrypt it.

To encrypt a character, you first find the column on the chart corresponding to the character in the plaintext, e.g. the character M (circled in blue). Next, find the row starting with the key character, e.g. the character B (circled in red). Finally, find where

the plaintext column and the key row intersect, e.g. the character N (circled in red). Continue this for each character.

 

 

 

MEMORY 

BADBAD 

N

    

 

 

MEMORY 

BADBAD 

NE

   

 

 

 

 

 

 

 

 

 

 

 

 

 

MEMORY 

BADBAD 

NEP

    

 

Continue until all characters have been encrypted: 

Input = MEMORY (plaintext)

Key = BADBAD (key)

output= NEPPRB (cypher-text)

Decrypting is the opposite of encrypting. To decrypt NEPPRB first write the key under the cypher-text. Then find the row starting with the key character. Next, move across that row until you find the cypher-text character. The cypher-text character’s column is the plaintext column.

 

NEPPRB

BADBAD

  M

   

 

 

 

NEPPRB

BADBAD

  ME

   

 

 

NEPPRB

BADBAD

 MEM

   

 

Continue until the cypher-text has been decrypted: 

Input = NEPPRB

Key = BADBAD

Output = MEMORY

 

(80 points): Read the comments in the template file “project5_template.asm” and finish (1) - (8)

At the top of your "asm" file, give a brief description of the program, author name and last modified date in the form of comments.

For the code, explain what each assembly line means in plain English. Your comment should be meaningful and reflect the code correctly.