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CMSC411 Project Solution


Objective:
To experience the design issues of advanced computer architectures through the design of a simulator for a simplified MIPS computer using high level programming languages. Project Statement:
Consider a simplified MIPS computer that follows the design discussed in class and in the textbook while accepting only the following subset of the instructions:
Instruction Class Instruction Mnemonic
Data Transfers LW, SW, LI
Arithmetic/ logical ADD, ADDI, MULT, MULTI, SUB, SUBI
Control BEQ, BNE, J
Special purpose HLT (to halt the simulation)
Develop an architecture simulator for the MIPS computer that accepts as an input a program in the MIPS assembly using the above subset of instructions. The output of simulator will be a file containing the cycle time of each instruction in every stage. It also has to report the instruction and data cache accesses as output example that comes later.
The organization of I-
Cache is direct-mapped with 4 blocks and the block size is 4 words. In addition, the architecture has a data cache (D-Cache) with hit time of one cycle. D-Cache is a
Figure 1: Block diagram description of the organization of the pipeline processor
2-way set associative with a total
Number of Cycles Instructions
1 Cycle BEQ, BNE, J, LW, SW, LI
2 Cycles ADD, ADDI, SUB, SUBI
3 Cycles MULT, MULTI
Data forwarding is possible from the MEM stage to the EX 1 & ID stages, from the EX 1, 2, 3 stages to ID stage, from EX 2, 3 to EX 1. Branches are resolved in the ID stage. Meanwhile the IF stage will go ahead and fetch the next instruction, in other words, always “not-taken prediction” will be used in IF stage. If we find out in the ID stage that the outcome of a branch is taken, the control unit will flush the IF stage (inserting a bubble) and update the program counter so IF in next cycle will start fetching from the branch target address.
The project executable should be named “simulator”. The format of the command line shall be as follows:
“simulator inst.txt data_segment.txt output.txt”
◼ The first input file should be the instruction file “inst.txt” that consists of assembly language code beginning at memory location 0x0 and is based on Table 1. Your program should ignore multiple white-spaces and use “,” as the separator for operands. Moreover, there should be LABELS before some certain instruction so that branch instructions can easily specify the destination. The delimiter for separating Labels, operation, and operands is a “|”.
◼ The second input file should contain data words to be placed in memory beginning at memory location 0x100. You can assume that the size of data segment is 32 words; meaning that the test cases will not require access to more than 32 words of memory. Registers will be initialized using the LI instruction. ◼ The last file is for storing the output of the simulator in.
Note: input files’ role will be defined based on their position in argument list. The names and their paths might be different and your simulator should not be restricted to specific name(s) or path(s).
The simulator is to be developed in the programming language of your choice. However, you MUST submit a “MAKEFILE” that automates the compilation of your project. For those using Java or Python, not C, making a “MAKEFILE” could be quite burdensome. In that case, you MUST submit a simple shell script file named
“make.sh” to automate the compilation. Please also include execution syntax in README file. For example, “java simulator inputFile.asm data.txt output.txt”. If you used ant and have a build.xml file, please make sure to include it in your project.
Input files format and considerations:
• You will have one instruction on each line.
• We are not going to test your input parser by feeding it with bad input files.
• Number of White Spaces (space, tab, enter) should not be a problem for your input parser.
• Your program should not be case sensitive. (e.g ADDI, addi, AddI, Addi, aDdi … are all same)
• You should strongly stick to the format of MIPS instructions. For example if you implement the load immediate as, “LI 1, R1”, it will be wrong (the correct format is LI R1, 1).
Output file format:
Use the example in project description as your guideline for output file. Do not put extra information such as your name in your output file.
Example
Consider the following input assembly program:
LI R1, 100h # addr = 0x100;
LW R3, 0(R1) # boundary = *addr;
LI R5, 1 # i = 1;
LI R7, 0h # sum = 0;
LI R6, 1h # factorial = 0x01;
LOOP: MULT R6, R5, R6 # factorial *= I;
ADD R7, R7, R6 # sum += factorial;
ADDI R5, R5, 1h # i++;
BNE R5, R3, LOOP
HLT


data_segment.txt
00000000000000000000000000000010
00000000000000000000000000000001
00000000000000000000000000000011
00000000000000000000000000010101
00000000000000001111111111111000
00000000000000000000000000000011
00000000000000000000000000000001
00000000000000001111100110100110
00000000000000000001010101010101
00000000000001101101010011110101
00000000000001000010101110010101
00000000000001101101111001010101
00000000000000000101010101110100
00000000000001001010101011110101
00000000000111101110000000000000
00000000000001101101010011110100
00000000000000001111111111111111
00000000000000001111100010100110
00000000000000001010101101110110
00000000000101011010011110101011
00000000000100000000000000000111
00000000000000000010000101010101
00000000001001110101010100010100
00000000101010101010101010101111
00000100010010010101110000001010
00000000000000001111111111111111
00000000000000000010101110101101
00000000000000000000000000000000
00000000000001101101010011110101
00000000000000000000000001100001
00000000000000110000101010101001
00000000000000000000010101010101

The output should be: (Numbers represent the clock cycle that instruction leaves each stage)
Note that the execution cycle number is the cycle of the last stage (=EX3) for all instructions. Branching instructions terminate in the EX1 stage and does not have entries in the MEM and WB stages.
Cycle Number for Each Stage IF ID EX3 MEM WB
LI R1, 100h 13 14 17 18 19
LW R3, 0(R1) 14 15 18 41 42
LI R5, 1 15 16 41 42 43
LI R7, 0h 16 17 42 43 44
LI R6, 1h 29 30 43 44 45
LOOP: MULT R6, R5, R6 30 41 44 45 46
ADD R7, R7, R6 41 42 47 48 49
ADDI R5, R5, 1h 42 45 48 49 50
BNE R5, R3, LOOP 55 56 59
HLT 56 59
Total number of access requests for instruction cache: 10
Number of instruction cache hits: 7
Total number of access requests for data cache: 1
Number of data cache hits: 0

Execution Trace (to explain the output):
The following is a detailed trace of execution of the above program:

Instruc tions Cycles
1 2 3 4 5 6 7 8 9 10
LI R1, 100h stall stall stall Stall stall stall stall stall stall stall
LW R3, 0(R1)
LI R5, 1
LI R7, 0h
LI R6, 1h
The stall at cycle 1 is caused by an I-Cache miss.
11 12 13 14 15 16 17 18 19 20
LI R1, 100h stall stall IF ID EX1 EX2 EX3 MEM WB
LW R3, 0(R1) IF ID EX1 EX2 EX3 stall stall
LI R5, 1 IF ID EX1 EX2
LI R7, 0h IF ID EX1
LI R6, 1h stall stall stall stall
LOOP: MULT R6, R5, R6
ADD R7, R7, R6
ADDI R5, R5, 1h
BNE R5, R3, LOOP
21 22 23 24 25 26 27 28 29 30
LI R1, 100h
LW R3, 0(R1) stall stall stall stall stall stall stall stall stall stall
LI R5, 1
LI R7, 0h
LI R6, 1h stall stall stall stall stall stall stall stall IF ID
LOOP: MULT R6, R5, R6 IF
ADD R7, R7, R6
ADDI R5, R5, 1h
BNE R5, R3, LOOP
HLT
Note that data dependency so far did not cause stalls and resolved by data forwarding.
31 32-40 41 42 43 44 45 46 47 48
LI R1, 100h
LW R3, 0(R1) stall stall MEM WB
LI R5, 1 EX3 MEM WB
LI R7, 0h EX2 EX3 MEM WB
LI R6, 1h EX1 EX2 EX3 MEM WB
MULT R6, R5, R6 ID EX1 EX2 EX3 MEM WB
ADD R7, R7, R6 IF ID stall stall EX1 EX2 EX3 MEM
ADDI R5, R5, 1h IF stall stall ID Ex1 EX2 EX3
BNE R5, R3,LOOP sta ll stall stall stall
HLT

49 50 51 52 53 54 55 56 57 58 59 60
LI R1, 100h
LW R3, 0(R1)
LI R5, 1
LI R7, 0h
LI R6, 1h
MULT R6, R5, R6
ADD R7, R7, R6 WB
ADDI R5, R5, 1h MEM WB
BNE R5, R3, LOOP stall stall stall stall stall stall stall stall IF ID EX1
HLT IF ID

Submission Procedure
# CMSC 411, Spring 2011, Term project Makefile simulator:
gcc project.c -o simulator clean:
-rm simulator *.o core*
First you need to ensure the MAKEFILE and the source code files are in the same directory. Then run make. An executable named simulator should appear in the same directory. Ensure that simulator runs correctly, and then run make clean. Check to ensure that simulator was deleted from the directory.
Submit all of your project files in a zip file to blackboard:

Instruction Format and Semantics:
Example Instruction Instruction Name Meaning
LW R1, 30(R2) Load word Regs[R1]<- Mem[30+Regs[R2]]
SW R3, 500(R4) Store word Mem[500+regs[R4]]<-Regs[R3]
LI R8, 42 Load immediate Regs[R8] <- 42
LI R8, -42 * Load immediate Regs[R8] <- (-42)
ADD R1,R2,R3 Add signed Regs[R1] <- Regs[R2] + Regs[R3]
ADDI R1,R2, 3 Add immediate signed Regs[R1] <- Regs[R2] + 3
SUB R1,R2,R3 Sub signed Regs[R1] <- Regs[R2] - Regs[R3]
SUBI R1,R2, 3 Sub immediate signed Regs[R1] <- Regs[R2] - 3
AND R1,R2,R3 Bitwise AND Regs[R1] <- Regs[R2] & Regs[R3]
ANDI R1,R2, 3 Bitwise AND-immediate Regs[R1] <- Regs[R2] & 3
OR R1,R2,R3 Bitwise OR Regs[R1] <- Regs[R2] | Regs[R3]
ORI R1,R2, constant Bitwise OR-immediate Regs[R1] <- Regs[R2] | constant
J LABEL Unconditional jump PC <-LABEL
BNE R3, R4, name Branch not equal If(R3 != R4) PC<-name
BEQ R3, R4, name Branch equal If(R3 == R4) PC<-name
MULT R1, R2, R3 Multiply signed Regs[R1] <- Regs[R2] * Regs[R3]
MULTI R1, R2, constant Multiply immediate signed Regs[R1] <- Regs[R2] * constant
* Immediate values can be positive or negative

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